Mix Design Of Concrete As Per IS 10262

Mix Design Of Concrete As Per IS 10262

Join us on Youtube (Subscribers - 701K) Join Now
Join us on WhatsApp Join Now
Join us on Facebook Join Now
Join us on Telegram Join Now
Join us on Instagram Join Now
Join us on Pinterest Join Now

In this tutorial, we are going to learn How to Do Mix Design Of Concrete As Per IS Code 10262 in SSD Condition as well as Moisture Content Condition

How To Do Mix Design Of Concrete As Per IS Code 10262 | SSD Condition | Moisture Content Condition

 The process of selecting suitable ingredients of concrete and determining their relative proportions with the object of producing concrete of certain minimum strength and durability as economically as possible is defined as MIX DESIGN.

Main Role of Mix Design

  • To achieve the stipulated minimum strength and durability.
  • To make the concrete economical.
 

GIVEN

Grade Of Concrete = M35
 
Characteristics Compressive Strength Required infield at 28 days = 35 MPA
 
Types Of Exposure = Moderate
 
Design Mix Target Slump = 150 – 175 mm
 
Maximum size of Coarse Aggregate = 20 mm
 
Fine Aggregate = ZONE – III
 
Specific Gravity of Cement = 2.93
 
Specific Gravity of Water = 1
 
Specific Gravity of Admixture = 1.121
 
Specific Gravity of Coarse Aggregate = 2.82
 
Specific Gravity of Fine Aggregate = 2.65
 
Water Absorption of Coarse Aggregate = 0.86 %
 
Water Absorption of Fine Aggregate = 1.25 %
 

1. CONDITION: SSD

TARGET MEAN STRENGTH OF CONCRETE

f´ck = f ck + 1.65 S

f´ck = 35 + 1.65 x 5

f´ck = 43.25 N/mm²

Where, f´ck = Target Mean Compressive Strength at 28 days in N/mm²

f ck = Characteristics Compressive Strength at 28 days in N/mm²

S = Standard Deviation in N/mm²

1.65 = Tolerance Factor

DETERMINATION OF WATER CEMENT RATIO

Water-Cement ratio depends on Exposure. Here Exposure is MODERATE.

As per Table 5 of IS 456: 2000 (Page-20),

Maximum Water-Cement ratio = 0.5

Based on Site Experience, Adopt water-cement ratio = 0.5-0.05 = 0.45

DETERMINATION OF WATER CONTENT

From Table 2 of IS 10262: 2009 (Page-3), We get that

Maximum water content for 20 mm coarse aggregate = 186 Litres

[NOTE: This value is for 25 mm to 50 mm slump range. Ref : IS : 10262 : 2009, Clause 4.2, Page-2]

Now, Our Targeted Slump is 150-175 mm

[NOTE: As per IS 10262: 2009, Clause 4.2, we can increase 3% for every additional 25 mm slump]

Estimated water content for 175 mm slump = 186 + (15 x 186 / 100) = 213.9 Litres

As admixture is used, the water content can be reduced by 15% and above.

The actual water to be used = 213.9 – (15 x 213.9 / 100) = 181.82 Litres

CALCULATION OF CEMENT CONTENT

As per Table 5 of IS 456: 2000, Page-20

For Moderate Exposure, Minimum Cement = 300 Kg/m³

Water Cement ratio = 0.45

Water Used = 181.82 Litres

Cement Content = Water Content / Water-Cement ratio

Cement Content = 181.82 / 0.45 = 404 Kg/m³

Which is greater than 300. Hence OK

CALCULATION OF VOLUME OF COARSE AND FINE AGGREGATE CONTENT

From Table 3 of IS 10262: 2009, 
 
Volume of Coarse Aggregate corresponding to 20 mm size aggregate and Fine Aggregate Zone – III for Water cement ratio of 0.5 = 0.64
 
Now, Actual Water-Cement ratio = 0.45
 
It is less by (0.5 – 0.45) = 0.05
 
As the Water-Cement ratio is reduced, it is desirable to increase the coarse aggregate proportion to reduce the fine aggregate.
 
The Coarse Aggregate is increased at the rate of 0.01 for every decrease in Water-Cement ratio of 0.05
 
For a decrease of every 0.05 W/C ratio = Coarse Aggregate increased by 0.01
 
For a decrease of every 1 W/C ratio = Coarse Aggregate increased by 0.01/0.05
 
For decrease of every 0.05 W/C ratio = Coarse Aggregate increased by (0.01 x 0.05 / 0.05) = 0.01
 
Corrected Proportion of Volume of Coarse Aggregate = 0.64 + 0.01 + 0.65
 
Since it is angular aggregate & concrete is to be pumped, the coarse aggregate can be reduced by 10% [IS 10262: 2009, Clause 4.4.1, Page-3]
 
By reducing 10% we get = 0.65 – (10 x 0.65 / 100) = 0.585 
 
So, Volume of Coarse Aggregate = 0.585
 
Volume of Fine Aggregate = 1 – 0.585 = 0.415
 

DESIGN MIX CALCULATION (Ref IS 10262: 2009)

The Mix Design Calculation per unit volume of concrete shall be as follows – 
 
The volume of Concrete – 1 m³
 
The volume of Cement = Mass of Cement / (Sp. Gravity of Cement x 1000)
      = 404 / (2.93 x 1000) = 0.138 m³
 
The volume of Water = Mass of Water / (Sp. Gravity of Water x 1000)
   = 181.82 / (1 x 1000) = 0.182 m³
 
Volume of Admixture = Mass of Admixture / (Sp. Gravity x 1000)
 
Assuming a dosage of 1.2% by weight of cementitious material and assuming and Sp. Gravity as 1.121
 
= (1.2 x 404 / 100) / (1.121 x 1000) = 0.004 m³
 
The volume of Entrapped Air = 2% for 20 mm Coarse Aggregate
 
        = 2/100 = 0.02 m³
 
[NOTE: As per IS 10262: 2009, the percentage of entrapped air is zero, Still 2% is considered on practical experiences]
 
The volume of All Aggregate (Coarse + Fine) = Volume of Concrete – (Volume of Cement + Volume of Water + Volume of Admixture + Volume of Entrapped Air)
 
= 1 – (0.138 + 0.182 + 0.004 + 0.02) = 0.656 m³
 
Mass of Coarse Aggregate = Volume of All Aggregate x Volume of Coarse Aggregate x Sp. Gravity x 1000
         = 0.656 x 0.585 x 2.82 x 1000 = 1082.2 Kg
 
Mass of Fine Aggregate = Volume of All Aggregate x Volume of Fine Aggregate x Sp. Gravity x 1000
     = 0.656 x 0.415 x 2.65 x 1000 = 721.4 Kg
 

PROPORTION OF TRIAL MIX : 1

Cement = 404 Kg/m³
 
Water = 181.82 Kg/m³
 
Fine Aggregate = 721.4 Kg/m³
 
Coarse Aggregate = 1082.2 Kg/m³ [60% of 20 mm ; 40% of 10 mm]
 
Admixture = 4.848 Kg/m³
 
Water-Cement Ratio = 0.45
 

2. CONDITION: MOISTURE CONTENT

Water Absorption (In SSD Condition)
 
Coarse Aggregate = 0.86%
Fine Aggregate = 1.25%
 
Due to Rain or by somehow, All aggregates mixed with water.
 
Free Moisture Content in Coarse Aggregate = 2%
Free Moisture Content in Fine Aggregate = 3%
 
Actual Moisture Content in Coarse Aggregate = 2 – 0.86 = 1.14%
Actual Moisture Content in Fine Aggregate = 3 – 1.25 = 1.75%
 
In SSD Condition From Mix Design, we got
 
Coarse Aggregate = 1082.2 Kg/m³
Fine Aggregate = 721.4 Kg/m³
Water = 181.82 Kg/m³
 
Corrected Mass of Coarse Aggregate = 1082.2 + (1.14 x 1082.2 / 100)
= 1082.2 + 12.34 = 1094.54 Kg
 
Corrected Mass of Fine Aggregate = 721.4 + (1.75 x 721.4 / 100)
= 721.4 + 12.62 = 734.02 Kg
 
Corrected Mass of Water = 181.82 – 12.34 – 12.62 = 156.86 Kg
 
 
Below I Am Uploading My Hand Made Documents For You Only On Your Request, So That You Can Download It From Here. But One Thing Keep In Mind That This Is Only The Hand Made Notes.
 
If You Want Detailed Knowledge Then Watch My Video On YouTube Channel: Civil Learning Technology.  I Am Telling This Because Many Important Points I Have Covered During Making Of Video, So If You Want To Know In Detail Then Watch My Video On YouTube Which is Given Below.
 
SSD CONDITION
 
SSD CONDITION1
SSD CONDITION 2
SSD CONDITION 3
SSD CONDITION 4
SSD CONDITION 5
SSD CONDITION 6
SSD CONDITION 7
 
MOISTURE CONTENT CONDITION

Mix Design Of Concrete As Per IS Code 10262 WATER CONTENT
I hope you find this information useful. If there is something that I have missed or I do not know, you can comment and tell me which I will try to rectify as soon as possible.
 
If you have liked this post of mine, then use the social link given below and share it among your friends on social media. Thanks
 
SHARE THIS POST, IF YOU LIKE IT !!
Padhega India Tab Hi Badhega India | पढ़ेगाइंडियातबहीबढ़ेगाइंडिया

 

RECOMMENDED POSTS FOR YOU:

9 thoughts on “Mix Design Of Concrete As Per IS 10262”

Leave a Comment